Question 184302
let:
 x be the first odd integer
 x + 2 be the 2nd odd integer
 x + 4 be the 3rd odd integer
solution:
 1st odd integer + 2nd odd integer + 3rd odd integer = 69
 x + (x+2) + (x+4)= 69
 3x + 6 = 69
 3x = 69 - 6
 3x = 63 (dividing both sides by three)
 x = 21
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 x=21
 x+2=23
 x+4=25

therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25...