Question 183861
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{{{x= 6-4y}}},---------->EQN 1 {{{y=(-x+6)/4}}}
{{{2x-3y=1}}},---------->EQN 2 {{{y=(2x-1)/3}}}
Substitute EQN 1 in EQN 2:
{{{2*highlight(6-4y)-3y=1}}}
{{{12-8y-3y=1}}}
{{{12-1=8y+3y}}}
{{{11=11y}}}---->{{{cross(11)1/cross(11)1=cross(11)y/cross(11)}}}
{{{highlight(y=1)}}}, subst. in EQn 1
{{{X=6-4(1)=6-4}}}
{{{highlight(x=2)}}}
When we graph the eqn's, the point of intersection will be (2,1):
{{{drawing(350,350,-5,5,-5,5,grid(1),graph(350,350,-5,5,-5,5,(-x+6)/4,(2x-1)/3),green(circle(2,1,.15)))}}}-----> RED, EQN 1; GREEN, EQN 2
Thank you,
Jojo</pre>