Question 184289
Let x = side of the square.

{{{x^2}}} = area of the square
{{{4x}}} = perimeter of the square


{{{x^2 = 4x-3}}}
{{{x^2 -4x+3=0}}}

{{{(x-3)(x-1)=0}}}

{{{x=3}}}  or {{{x=1}}}


The only answer that is greater than 1 is x= 3.


R^2