Question 184140
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*[tex \LARGE 1.\ \ \ \ \ \ \ \ \ \ \ 4x-3y=15]
*[tex \LARGE 2.\ \ \ \ \ \ \ \ \ \ \ x-2y=0]


Solve equation 2. for <i>x</i>:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \ x=2y]


Substitute 2<i>y</i> for <i>x</i> in equation 1.:


*[tex \LARGE 1.\ \ \ \ \ \ \ \ \ \ \ 4(2y)-3y=15]


Now solve for <i>y</i>.  Once you have found the value for <i>y</i>, substitute that value into either of the original equations to solve for <i>x</i>.  I suggest you use equation 2 for this step.


John
*[tex \Large e^{i\pi} + 1 = 0]
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