Question 184110
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In the first place, you don't have an equation, you have an inequality.  Equations have equal signs, and inequalities have inequality signs.


That being said, you solve inequalities the same way you solve equations -- with one important exception.  That is to say that you can add the same thing to both sides, multiply both sides by the same thing, and/or take a root of both sides.  The only exception to the process is when multiplying an inequality by a negative number.  If you do this, then you must reverse the sense of the inequality (greater than becomes less than, for example).


So for your problem:


*[tex \LARGE \text{          }\math \frac{3}{4} + 2y < y - \frac{2}{3}]


Add *[tex \Large -\frac{3}{4}] to both sides:


*[tex \LARGE \text{          }\math 2y < y - \frac{2}{3} -\frac{3}{4} = y - \frac{8}{12} -\frac{9}{12} = y - \frac{17}{12}]


Then add *[tex \Large -y] to both sides:


*[tex \LARGE \text{          }\math 2y - y < - \frac{17}{12} \ \ \Rightarrow\ \ y < - \frac{17}{12}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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