Question 184065
Philip has 10 coins in his pocket. Philip has the same number of pennies as quarters and the same number of dimes as nickels. He also has one more nickel than he does pennies. If he has 97 cents, how many coins of each type does he have?
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Value Equation: p + 25q + 10d + 5n = 97
Quantity Eqations:
p = q
d = n
n = p + 1
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Substitute to get an equation in "p":
p + 25p + 10(p+1) + 5(p+1) = 97

p + 40p + 15 = 97
41p = 82
p = 2 (# of pennies)
q = 2 (# of quarters)
n = 2+1 = 3 (# of nickels)
d = 3 (# of dimes)
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Cheers,
Stan H.