Question 184102
{{{(49-x^2)/(2x^2-9x-35)}}} Start with the given expression



{{{(-(x-7)(x+7))/(2x^2-9x-35)}}} Factor the numerator



{{{(-(x-7)(x+7))/((x-7)(2x+5))}}} Factor the denominator



{{{(-highlight((x-7))(x+7))/(highlight((x-7))(2x+5))}}} Highlight the common terms.



{{{(-cross((x-7))(x+7))/(cross((x-7))(2x+5))}}} Cancel out the common terms.



{{{-(x+7)/(2x+5)}}} Simplify



So {{{(49-x^2)/(2x^2-9x-35)}}} simplifies to {{{-(x+7)/(2x+5)}}} 



In other words, {{{(49-x^2)/(2x^2-9x-35)=-(x+7)/(2x+5)}}} where {{{x<>-5/2}}} or {{{x<>7}}}