Question 184091
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Given: (3,-12) and (-4,2)
Via Point-Slope Form: {{{m=(y[2]-y[1])/(x[2]-x[1])}}}
where{{{system(y[2]=2,y[1]=-12,x[2]=-4,x[1]=3)}}}
Then,
{{{m=(2-(-12))/(-4-3)=(2+12)/-7=14/-7=-2}}} Slope
Then via point (3,-12) thru Slope-Intercept{{{y=mx+b}}}:
{{{-12=-2(3)+b}}}
{{{b=-12+6=-6}}}, Y-Intercept
Via point (-4,2):
{{{2=-2(-4)+b}}}
{{{b=2-8=-6}}}, the same (should be)
Then it follows-----> {{{highlight(y=-2x-6)}}}, or {{{highlight(2x+y=-6)}}} Std Form
We'll see the graph:
{{{drawing(400,400,-10,6,-15,6,grid(1),graph(400,400,-10,6,-15,6,-2x-6),green(circle(3,-12,.15)),green(circle(-4,2,.15)))}}}
Thank you,
Jojo</pre>