Question 184077
 If a basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang time function V=48T^2.
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Use basic algebra rules to solve for T, (isolate T by itself on the left)
write it:
48T^2 = V
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Substitute 20 for T
48T^2 = 20
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Divide both sides by 48
T^2 = {{{20/48}}}
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Find the square root of both sides to change T^2 to just T
T = {{{sqrt(20/48)}}}
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Enter {{{sqrt(20/48)}}} into a calc, it will = .64549.. rounded to .6 sec
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You would do it exactly the same way if it were 35/48
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Does this make sense to you now?