Question 184066
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The area of the square is *[tex \Large (2x)^2 = 4x^2]


The area of the added semi-circle is *[tex \Large \pi x^2]


The area of the subtracted semi-circle is *[tex \Large \pi \left(\frac{x}{2}\right)^2 = \frac{\pi x^2}{4}]


Add 'em up:

 
*[tex \LARGE \text{          }\math A(x) = 4x^2 + \pi x^2 - \frac{\pi x^2}{4} =  \left(4 + \frac{3\pi}{4}\right)x^2]


Mighty goofy looking sign, if you ask me.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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