Question 184067
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The area of a square is given by *[tex \Large A = s^2], so you can say:


*[tex \LARGE \text{          }\math s = sqrt{A}].


The perimeter of a square is given by *[tex \Large P = 4s], so by substitution:


*[tex \LARGE \text{          }\math P(A) = 4 sqrt{A}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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