Question 25691
Solve for x:
{{{2x^2 = 288}}} Notice that only the x is squared, not the 2.  Divide both sides of the eqaution by 2.
{{{x^2 = 144}}} Now take the square-root of both sides.
{{{sqrt(x^2) = x}}} and {{{sqrt(144) = 12}}} + or -
x = + or - 12