Question 184030
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{{{x+2y=10}}}-------------------------> EQn 1
{{{2X+2Y=12}}}------------------------> EQN 2
Working both eqn's via Slope-Intercept Form, {{{y=mx+b}}}
In EQN 1,
{{{2y=-x+10}}}--->{{{cross(2)y/cross(2)=(-x+10)/2}}}
{{{y=(-1/2)x+(10/2)=(-1/2)x+5}}}, EQN 1.1
Let {{{f(y)=0}}}
{{{0=(-1/2)x+5}}}
{{{(1/2)x=5}}}---->{{{highlight(x=10)}}}
Let {{{f(x)=0}}}
{{{y=(-1/2)(0)+5}}}
{{{highlight(y=5)}}}
In EQN 2:
{{{2y=-2x+12}}}----->{{{cross(2)y/cross(2)=(-2x+12)/2}}}
{{{y=(-2/2)x+(12/2)}}}
{{{y=-x+6}}}, EQN 2.2
let {{{f(y)=0}}}
{{{2*0=-2x+12}}}
{{{2x=12}}}---->{{{cross(2)x/cross(2)=cross(12)6/cross(2)}}}
{{{highlight(x=6)}}}
let {{{f(x)=0}}}
{{{2y=-2*0+12}}}
{{{cross(2)y/cross(2)=cross(12)6/cross(2)}}}
{{{highlight(y=6)}}}
Mark x & y on EQN 1.1 and EQN 2.2 on the graph:
{{{drawing(350,350,-8,15,-5,8,grid(1),graph(350,350,-8,15,-5,8),green(circle(10,0,.20)),green(circle(0,5,.2)),blue(circle(6,0,.2)),blue(circle(0,6,.2)))}}}----->{{{drawing(350,350,-8,15,-5,8,grid(1),graph(350,350,-8,15,-5,8,(-1/2)x+5,-x+6),green(circle(10,0,.2)),green(circle(0,5,.2)),blue(circle(6,0,.2)),blue(circle(0,6,.2)))}}}---> RED, EQN.1; GREEN, EQN 2

Thank you, 
Jojo</pre>