<PRE><B>Question 183995</B>
write an equation for the following function in vertex form: 
then it shows a parabola,
the vertex is (2,1) and the point is (-2,5)
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Form (x-h)^2 = 4p(y-k)
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(h,k) is the vertex (2,1)
substitute to get:
(x-2)^2 = 4p(y-1)
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Let y = 5 when x = -2

(-2-2)^2 = 4p(5-1)
16 = 4p(4)
p = 1
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Equation:
(x-2)^2 = 4(y-1)
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Cheers,
Stan H.</PRE>