Question 183963
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The <i>x</i>-intercept is an ordered pair of the form (<i>a</i>,0), where <i>a</i> is the value of <i>x</i> when <i>y</i> = 0.  It is called the <i>x</i>-intercept because this ordered pair describes the point where the line represented by your equation crosses (or 'intercepts') the <i>x</i>-axis.


So, all you need to do is substitute 0 for <i>y</i> in your equation and then solve the result for <i>x</i>.


*[tex \LARGE \text{          }\math 5x + 15(0) =30]


By the way, finding a <i>y</i>-intercept, i.e. the point (0,<i>b</i>), is just the opposite process, that is substitute 0 for <i>x</i> in your equation. 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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