Question 183956
The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form.
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Let width = W.
Then Length = "2W+3"
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Equation:
diagonal^2 = leg^2 + leg^2
d^2 = x^2 + (2x+3)^2
d^2 = x^2 + 4x^2 + 12x + 9
d^2 = 5x^2 + 12x + 9
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d = sqrt(5x^2+12x+9)
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Cheers,
Stan H.