Question 183932
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Given:
Line equation{{{system(2x+y=-6)}}}
Via Slope-Intercept Form----->{{{y=mx+b}}}
It follows, 
{{{y=-2x-6}}}, where{{{system(Slope=m=-2,yIntercept=b=-6)}}}
Then, we get the x & y intercepts:
{{{f(y)=0}}}
{{{0=-2x-6}}}--------->{{{2x=-6}}}
{{{cross(2)x/cross(2)=cross(-6)3/cross(2)}}}
{{{highlight(x=-3)}}}, x -intercept
{{{f(x)=0}}}
{{{y=-2(0)-6}}}
{{{highlight(y=-6)}}}
We'll see the graph:
{{{drawing(350,350,-8,8,-8,8,grid(1),graph(350,350,-8,8,-8,8,-2x-6),green(circle(-3,0,.15)),green(circle(0,-6,.15)))}}}
Thank you,
Jojo</pre>