Question 183896
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The area of a triangle is given by:


*[tex \LARGE \text{          }\math A = \frac {bh}{2}]


You are given that:


*[tex \LARGE \text{          }\math b - 3 = h]


Substituting:


*[tex \LARGE \text{          }\math \frac {b(b - 3)}{2} = 77]


*[tex \LARGE \text{          }\math b^2 - 3b = 154]


*[tex \LARGE \text{          }\math b^2 - 3b - 154 = 0]


Solve the quadratic by factoring and exclude the extraneous negative root.  The positive root will be the measure of the base of the triangle.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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