<PRE><B>Question 183890</B>
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The opposite polynomial of a polynomial &lt;i&gt;P&lt;/i&gt; is the polynomial -&lt;i&gt;P&lt;/i&gt; such that:


*[tex \LARGE \text{          }\math P + (-P) = 0]


Therefore, the opposite of:


*[tex \LARGE \text{          }\math -5x^2-3x+7]


is &lt;i&gt;&lt;b&gt;not&lt;/b&gt;&lt;/i&gt;


*[tex \LARGE \text{          }\math -5x^2--3+-7]


Rather it is:


*[tex \LARGE \text{          }\math -1(-5x^2-3x+7) = (-1)(-5x^2)+(-1)(-3x)+(-1)(7)=5x^2 + 3x -7]


Now if you add your polynomial and its opposite, the result will be zero.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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