Question 183854
<font face="Times New Roman" size="+2">


*[tex \LARGE \text{          }\math y=1/3x+1]


While I think you meant:


*[tex \LARGE \text{          }\math y=\frac{1}{3}x+1],


You might just as well have meant:


*[tex \LARGE \text{          }\math y=\frac{1}{3x}+1]


Which will produce a different result altogether.


Either way, the process is the same.  Let's assume you meant:


*[tex \LARGE \text{          }\math y=\frac{1}{3}x+1]


Step 1:  Pick a value, any value, for <i>x</i>.  Since it doesn't matter what value you select, I would pick something divisible by 3 since that will make the arithmetic easier.  So let's go ahead and use 3 for the first one.


Step 2: Substitute your selected value in place of <i>x</i> and then do the arithmetic required to determine the resulting value of <i>y</i>.


*[tex \LARGE \text{          }\math y=\frac{1}{3}(3)+1] 


*[tex \LARGE \text{          }\math y=1+1=2]


So, when <i>x</i> = 3, <i>y</i> = 2.


Step 3: Form the ordered pair (<i>x</i>,<i>y</i>):  (3, 2).


Repeat this process three more times with three different values for <i>x</i>. 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>