Question 183789
{{{(4-3i)*(2+i)}}} Start with the given expression.



{{{(4)(2)+(4)(i)+(-3i)(2)+(-3i)(i)}}} FOIL.



{{{8+4i-6i-3i^2}}} Multiply.



{{{8+4i-6i-3(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{8+4i-6i+3}}} Multiply.



{{{11-2i}}} Combine like terms.



So {{{(4-3i)*(2+i)=11-2i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=11}}} and {{{b=-2}}}