Question 183715
Differentiate the function. Do not expand any expression before differentiating: 
Use the chain rule as follows:
a) f(x)=[(2-x)^4+16]^3

f'(x) = 3[(2-x)^4+16]^2 * 4(2-x)^3 * (-1)

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b) f(x)=1/((x^2)-16)^5 
f(x) = ((x^2)-16)^-5

f'(x) = -5[((x^2)-16)^-4]*[2x]

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Cheers,
Stan H.