Question 183675


{{{(a^2-8a+12)/(3a-18)}}} Start with the given expression.



{{{((a-2)*(a-6))/(3a-18)}}} Factor {{{a^2-8a+12}}} to get {{{(a-2)*(a-6)}}}.



{{{((a-2)*(a-6))/(3(a-6))}}} Factor {{{3a-18}}} to get {{{3(a-6)}}}.



{{{((a-2)highlight((a-6)))/(3*highlight((a-6)))}}} Highlight the common terms. 



{{{((a-2)cross((a-6)))/(3*cross((a-6)))}}} Cancel out the common terms. 



{{{(a-2)/3}}} Simplify. 



So {{{(a^2-8a+12)/(3a-18)}}} simplifies to {{{(a-2)/3}}}.



In other words, {{{(a^2-8a+12)/(3a-18)=(a-2)/3}}} where {{{a<>6}}}