Question 25659
SEE THE FOLLOWING PROBLEM WHICH IS SIMILAR
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Two men, A and B, start toward each other at the same time from points 510 miles apart. If they travel 40 and 4 milea an hour respectively, in how many hours will they meet.
RELATIVE SPEED WHILE TRAVELLING IN OPPOSITE DIRECTION TO EACH OTHER = S1+S2=40+4=44 MPH.
INTIAL DISTANCE OF SEPERATION =510 MILES.
FINAL DISTANCE OF SEPERATION =0
HENCE DISTANCE TO BE COVERED TOGETHER = 510 -0 =510 MILES
TIME NEEDED =DISTANCE / RELATIVE SPEED = 510/44 HRS
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IN YOU CASE ,WE GET..WITH X AND X+6 SPEEDS AS GIVEN, 
8= 480/(X+X+6)
8(2X+6)=480
2X+6=480/8=60
2X=60-6=54
54/2=27.
HENCE THEIR SPEEDS ARE 27 AND 33 MPH.