Question 25661
y=x^2+6x-1
A) Let y=0:
x^2+6x-1=0
*[invoke quadratic "x",1,6,-1]
B) Complete the square:
  y= (x^2+6x+9)-1-9
  y=(x+3)^2-10
 y+10=(x+3)^2
 This is in "vertex" form:
 h=-3, k=-10
C) The axis of symmetry is x=-3

Cheers,
Stan H.