Question 25670
The center is at the midpoint of the diameter.  This is like the average of the x coordinates, and the average of the y coordinates.  So, add the x coordinates and divide by 2, add the y coordinates and divide by 2.

{{{x = ((-4) + (-8))/2= -12/2= -6}}}
{{{y = (10+0)/2= 5}}}


Coordinates of the center : (-6,5)


R^2 at SCC