Question 25666
You can start with x as the first positive even integer, the next positive even integer would be x+2 and the next one would be x+4. Now you could set up the inequality:
{{{x + (x+2) + (x+4) < 40}}} Solve for x.
{{{3x + 6 < 40}}} Subtract 6 from both sides.
{{{3x < 34}}} Divide both sides by 3.
{{{x < 11.33}}} But you want even integers, so use x = 10

10+12+14 = 36 < 40
8+10+12 = 30 < 40
6+8+10 =24 < 40
4+6+8 = 18 < 40
2+4+6 = 12 < 40
0+2+4 = 6 < 40