Question 25630
Let the first side be x
Let the second side be y
Let the third side be z
x+y+z=62 (equation 1) (1)
y = 2x---->2x-y=0 (equation 2) (2)
z = 12+2x ----> 2x-z=-12 (equation 3) (3)
Eliminate z
x+y+z=62 (1)
2x-z=-12 (3)
-------- --> add the following
3x+y=50 (set 1)
Add set 1 to equation 2
3x+y=50
2x-y=0
5x=50
x=10


y=2(10)
y=20


z=2(10)+12
z=32


Hence, the first side 10 cm, the second side is 20 cm, and the third side is 32 cm.
Paul.