<PRE><B>Question 183276</B>
 Grace starts jogging home at 5 km/hr. Will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. How long will it take Will to catch up to Grace?
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Grace DATA:
rate = 5 km/h ; time = x hrs ; distance = rt = 5x km
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Will DATA:
rate = 15 km/h ; time = (x-(1/6)) hrs ; distance = rt = 15(x-(1/6)) km
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Equation:
distance = distance 
5x = 15(x - (1/6))

5x = 15x - (5/2)
10x = (5/2)
x = 1/4 hr
x - (1/6) = (1/4)-(1/6) = (6-4)/24 = 2/24 = 1/12 hr. or 6 minutes

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Cheers,
Stan H.
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