Question 183192
What is the equation of the perpendicular bisector of the line between the points (2,2) and (6,6)?
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Find the point. The easiest way (always use the easiest) is to average x and y separately
(2+6)/2 = 4 (x and y in this case)
The mid-point is (4,4)
Now find the slope, m
m = diffy/diffx
m = (6-2)/(6-2)
m = 1
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The slope of lines perpendicular (there are an infinite number of them) have a slope that's the negative inverse.
m2 = -1
Then use
y-y1 = m2*(x-x1) where (x1,y1) is (4,4)
y-4 = -1(x-4)
y-4 = -x+4
x+y = 8