Question 183085
expanding __ (x^2)/16 + (256-32x+x^2)/16 = 10


multiplying by 16 and rearranging __ 2x^2-32x+256 = 160


subtracting 160 and dividing by 2 __ x^2-16x+48 = 0


factoring __ (x-12)(x-4) = 0


x equals 12 or 4 (which sum to 16)


one square is 9in^2 and the other is 1in^2