Question 182916
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Given a point on a line and the slope of the line, you can determine the equation of the line using the point-slope form:


*[tex \LARGE \text{          }\math y - y_1 = m(x - x_1)]


Where <i>m</i> is the slope, and *[tex \Large (x_1,y_1)] are the coordinates of  the given point.


The slopes of perpendicular lines are negative reciprocals, that is:


*[tex \LARGE \text{          }\math L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = \frac {-1}{m_2}]


So, take your given equation, solve for <i>y</i> to put it into slope intercept form:


*[tex \LARGE \text{          }\math y = mx + b]


The slope of the given line will be the coefficient on the <i>x</i> term.  Take the negative reciprocal (invert the fraction and put a minus sign in front of it) of that slope and with the given point you will have enough information to use the point-slope form to derive your required equation.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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