Question 182853
{{{2^(2x)-(2^5)^x-18=0}}}
{{{2^(2x)-2^(5x)-18=0}}}
{{{2^(2x)-2^(5x)=18}}}
Here's a graph of both {{{2^(2x)}}}(in red) and {{{2^(5x)}}}(in green).
{{{ graph( 300, 300, -5, 2, -2, 4, 2^(2x), 2^(5x)) }}}
The only time that {{{2^(2x)}}} is greater than {{{2^(5x)}}} is when x<0.
At that point, both values are less than one and their difference cannot equal 18.
When x>0, {{{2^(5x)}}} is always greater than {{{2^(2x)}}}, the difference cannot be 18.

There is no solution.