Question 182851
{{{(9bc/2a)/(6b/4a)}}}
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Change to a multiplication by "flipping" the denominator:
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{{{(9bc/2a)(4a/6b)}}}
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{{{(9bc)(2/6b)}}}
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{{{(9c)(2/6)}}}
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{{{(9c)(1/3)}}}
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{{{(3c)}}}
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So, yes, your answer is correct.