Question 182769
f(x) = -2x^2+2x+1
:
{{{f(x)=-2(x^2-2x)+1}}}
:
{{{f(x)=-2(x^2-x+(1/4))+1+(1/2)}}}
:
{{{f(x)=-2(x-(1/2))^2+(3/2)}}}
:
vertex is at (1/2,3/2)
:
line if symmetry is at x=1/2
:
maximum is at y=3/2
:
{{{graph(300,300,-10,10,-10,10,-2x^2+2x+1)}}}