Question 182730
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Step 1:  Divide the coefficient on the <i>x</i> term by 2.


Step 2:  Square the result.


Step 3:  Re-write the given constant term as the sum of the results of step 2 and some number.  You should now have an <i>x</i>-squared term, an <i>x</i> term, and two constant terms, the first of which is the result of step 2, and the sum of the two is the original constant term.


Step 4:  The first three terms are now a perfect square trinomial.  Factor it.  You should now have a binomial in <i>x</i> squared plus (or minus perhaps) a constant.


In this case <i>c</i> is 1, <i>h</i> will be the second term of the binomial, and <i>k</i> will be the leftover constant.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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