Question 182664
{{{2t(x - 2t) = y(x - y)}}}
{{{2tx - 4t^2 = xy - y^2}}}
Get the {{{x}}} terms on one side by
subtracting {{{xy}}} from both sides
{{{2tx - xy - 4t^2 = -y^2}}}
Add {{{4t^2}}} to both sides
{{{2tx - xy = 4t^2 - y^2}}}
Factor out {{{x}}} from the left side
{{{x*(2t - y) = 4t^2 - y^2}}}
{{{x = (4t^2 - y^2) / (2t - y)}}}
I can factor the numerator. It is the difference of 
two perfect squares like {{{a^2 - b^2 = (a + b)(a - b)}}}
{{{x = ((2t + y)(2t - y)) / (2t - y)}}}
{{{x = 2t + y}}} answer