Question 25581
to get the ratio between terms, you can use neighbouring terms.


First term = a
Second term = ar


ar/a is r, the common ratio


So, first term is 1 and second term is 1/2, so r is (1/2)/1 --> r=1/2


10th term is {{{ar^9}}} --> 1*(1/2)^9 --> 1/512


Sequence 1, 2, 4, 8, 16, ... are powers of 2: {{{2^0}}}, {{{2^1}}}, {{{2^2}}} etc


So, on 32nd square we would have {{{2^31}}} coins. 


jon.