Question 182506


{{{((x^2+12x+32)/(x+4))((3)/(x+8))}}} Start with the given expression.



{{{(((x+8)*(x+4))/(x+4))((3)/(x+8))}}} Factor {{{x^2+12x+32}}} to get {{{(x+8)*(x+4)}}}.



{{{(3*(x+8)*(x+4))/((x+4)(x+8))}}} Combine the fractions. 



{{{(3*highlight((x+8))*highlight((x+4)))/(highlight((x+4))*highlight((x+8)))}}} Highlight the common terms. 



{{{(3*cross((x+8))*cross((x+4)))/(cross((x+4))*cross((x+8)))}}} Cancel out the common terms. 



{{{3}}} Simplify. 



So {{{((x^2+12x+32)/(x+4))((3)/(x+8))}}} simplifies to {{{3}}}.



In other words, {{{((x^2+12x+32)/(x+4))((3)/(x+8))=3}}} where {{{x<>-4}}} or {{{x<>-8}}}