<PRE><B>Question 182627</B>
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Step 1:  Determine the slope of the line represented by the given equation.  Solve the given equation for &lt;i&gt;y&lt;/i&gt;.  Then the slope, &lt;i&gt;m&lt;/i&gt;, will be the resulting coefficient on &lt;i&gt;x&lt;/i&gt;.


Step 2:  Parallel lines have equal slopes.  That is to say:


*[tex \LARGE \text{          }\math L_1 \para L_2 \ \ \Leftrightarrow\ \ m_1 = m_2]


So, using the given point and the value of &lt;i&gt;m&lt;/i&gt; determined in step 1, use the point-slope form of the equation of a line to develop your desired equation.


*[tex \LARGE \text{          }\math P_1(x_1,y_1) = (8, 1)] so:


*[tex \LARGE \text{          }\math y - y_1 = m(x - x_1)] becomes


*[tex \LARGE \text{          }\math y - 1 = m(x - 8)]


Solve for &lt;i&gt;y&lt;/i&gt; to put your final equation in slope-intercept form.  You should notice that your answer will differ from the results of step 1 by only the value of the constant term.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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