Question 182602
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The perimeter of a rectangle is given by:


*[tex \LARGE \text{          }\math P = 2l + 2w]


But for this rectangle we know that the length is 3 inches longer than the width, so:


*[tex \LARGE \text{          }\math l = w + 3] which means that we can write:


*[tex \LARGE \text{          }\math P = 2(w + 3) + 2w]


and since we know that *[tex \Large P = 78], we can write:


*[tex \LARGE \text{          }\math 2(w + 3) + 2w = 78]


Solve for <i>w</i> to get the width, add 3 to get the length.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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