<PRE><B>Question 182559</B>
A merchant blends tea that sells for $2.85 lb with tea that sells for $2.60 lb 
to produce a 90 lb mixture that sells for $2.75 lab. How many pounds of each
type of tea does the merchant use in the blend?
:
Let x = amt of $2.85 lb tea
:
It says the resulting amt will be 90 lb, therefore:
(90-x) = amt of $2.60 lb tea
:
2.85x + 2.60(90-x) = 2.75(90)
:
2.85x + 234 - 2.6x = 247.5
:
2.85x - 2.60x = 247.5 - 234
:
.25x = 13.5
x = {{{13.5/.25}}}
x = 54 lb of $2.85 lb tea required
then
90 - 54 = 36 lb of $2.60 lb required
;
;
Check solution;
2.85(54) + 2.6(36) = 2.75(90)
153.9 + 93.6 = 247.5</PRE>