Question 182550
Quadratic Function 
Find the a: vertex
b: domain
c: range 
of f(x) = -2x^2 - 4x +3
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Put in vertex form:
2x^2 + 4x + ? = -y + 3 + ?
2(x^2+2x + 1) = -y + 3 + 2
2(x+1)^2 = -y + 5
(x+1)^2 = (-1/2)y + (5/2)
(x+1)^2 = (-1/2)(y - 5)
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Vertex: (-1,5)
domain: all Real Numbers
Range: all Real Numbers <= 5
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{{{graph(400,300,-10,10,-10,10,-2x^2-4x+3)}}}
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Cheers,
Stan H.