Question 182367
{{{b = a + 2}}}
{{{c = sqrt(a^2+b^2) = 2a - 2}}}
{{{sqrt(a^2+(a+2)^2) = sqrt(a^2+a^2+4a+4) = sqrt(2a^2+4a+4) = 2a-2}}}
{{{2a^2+4a+4 = (2a-2)^2 = 4a^2-4a+4}}}
{{{a^2+2a+2 = 2a^2-2a+2}}}
{{{-a^2+4a=0}}}
{{{a(-a+4)=0}}}
a = 0 or 4
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Since a triangle can't have a side of 0, a = 4
Not needed, but b = 6, c = {{{sqrt(52) = 2*sqrt(13)}}}