Question 182412
{{{2/(x+1) + 3/(x+2)}}}

We need to get a common denominator, which is {{{(x+1)(x+2)}}}.

{{{2*(x+2)/((x+1)(x+2))+3*(x+1)/((x+2)(x+1))}}}
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{{{((2x+4)+(3x+3))/((x+1)(x+2))}}}
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{{{(5x+7)/(x^2+3x+2)}}}