<PRE><B>Question 182419</B>
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You started correctly, and your final answer is correct, so maybe you just have a typo in your intermediate step.


Original length: 5&lt;i&gt;x&lt;/i&gt;
Original width: 4&lt;i&gt;x&lt;/i&gt;


New length:  5&lt;i&gt;x&lt;/i&gt; + 12


So the new area must be the Original Width times the New Length:


*[tex \LARGE \text{          }\math A_n = 4x(5x + 12) = 4x(5x) + 4x(12) = 20x^2 + 48x]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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