Question 3161
{{{x + 3 = sqrt(44 + 4x)}}} is the same as {{{(x + 3)^2 = 44 + 4x}}}. So we then get...


{{{x^2 + 6x + 9 = 44 + 4x}}}
{{{x^2 + 2x - 35 = 0}}}
(x+7)(x-5) = 0


so x+7=0 OR x-5=0
so x=-7, x=5


jon.