Question 182158
In matrix form it would look like,
[A]={{{(matrix(3,3,1,0,1,1,1,0,2,1,1))}}}
[x]={{{(matrix(3,1,x,y,z))}}}
[b]={{{(matrix(3,1,1,2,3))}}}
[A][x]=[b]
The solution is
[x]=[A]inv[b]
where [A]inv is the inverse of [A]
This is where the problem comes in.
The determinant of [A] is zero, there is no solution. 
Was that the difficulty you were having?