Question 182225
I need help factoring the difference of these cubes. 
54x^3-16y^3

= 2((3x)^3 - (2y)^3)

= 2(3x - 2y)((3x)^2 + (3x)(2y) + (2y)^2)

= 2(3x-2y)(9x^2 + 6xy + 4y^2)

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Cheers,
Stan H.