Question 182078


{{{(z-8)(z+3)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(z)-8)(highlight(z)+3)}}} Multiply the <font color="red">F</font>irst terms:{{{(z)*(z)=z^2}}}.



{{{(highlight(z)-8)(z+highlight(3))}}} Multiply the <font color="red">O</font>uter terms:{{{(z)*(3)=3*z}}}.



{{{(z+highlight(-8))(highlight(z)+3)}}} Multiply the <font color="red">I</font>nner terms:{{{(-8)*(z)=-8*z}}}.



{{{(z+highlight(-8))(z+highlight(3))}}} Multiply the <font color="red">L</font>ast terms:{{{(-8)*(3)=-24}}}.



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{{{z^2+3*z-8*z-24}}} Now collect every term to make a single expression.



{{{z^2-5*z-24}}} Now combine like terms.



So {{{(z-8)(z+3)}}} FOILs to {{{z^2-5*z-24}}}.



In other words, {{{(z-8)(z+3)=z^2-5*z-24}}}.